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Question

Physics Question on laws of motion

A 2kg 2 \, \, \text{kg } stone tied at the end of a string 1m1 m long is whirled along a vertical circle at a constant speed of 4ms14 \, m \, s^{- 1} . The tension in the string has a value of 52N52 N when the stone is

A

At the top of the circle

B

Half way down

C

At the bottom of the circle

D

Half way up

Answer

At the bottom of the circle

Explanation

Solution

Here, m=2kg,r=1m,v=4ms1m=2 \, kg,r=1 \, m,v=4 \, m \, s^{- 1} Tension at the bottom of the circle, TL=mg+mv2rT_{L}=mg+\frac{m v^{2}}{r} =20+2×421=52N=20+\frac{2 \times 4^{2}}{1}=52 \, N