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Question: A 2 m long rod of radius 1 cm which is fixed from one end is given a twist of 0.8 radians. The shear...

A 2 m long rod of radius 1 cm which is fixed from one end is given a twist of 0.8 radians. The shear strain developed will be

A

0.002

B

0.004

C

0.008

D

0.016

Answer

0.004

Explanation

Solution

rθ=Lϕ102×0.8=2×ϕϕ=0.004r \theta = L \phi \Rightarrow 10 ^ { - 2 } \times 0.8 = 2 \times \phi \Rightarrow \phi = 0.004