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Question

Physics Question on Current electricity

A 2kW2 \,kW boiler used for 1h/1\, h/day consumes the following electrical energy in thirty days

A

60 unit

B

120 unit

C

15 unit

D

6×1046\times 10^{4} unit

Answer

60 unit

Explanation

Solution

Number of units =P( in watt )×t( in hour )1000=\frac{P(\text { in watt }) \times t(\text { in hour })}{1000} \Rightarrow Number of units =2×103×1×301000=60=\frac{2 \times 10^{3} \times 1 \times 30}{1000}=60 unit