Solveeit Logo

Question

Question: A 2 kg mass starts from rest on an inclined smooth surface with inclination 30<sup>o</sup> and lengt...

A 2 kg mass starts from rest on an inclined smooth surface with inclination 30o and length 2 m. How much will it travel before coming to rest on a frictional surface with frictional coefficient of 0.25

A

4 m

B

6 m

C

8 m

D

2 m

Answer

4 m

Explanation

Solution

v2=u2+2as=0+2×gsin30v ^ { 2 } = u ^ { 2 } + 2 a s = 0 + 2 \times g \sin 30 ×2\times 2v=20v = \sqrt { 20 }

Let it travel distance ‘S’ before coming to rest

S=v22μg=202×0.25×10=4 mS = \frac { v ^ { 2 } } { 2 \mu g } = \frac { 20 } { 2 \times 0.25 \times 10 } = 4 \mathrm {~m}