Solveeit Logo

Question

Question: A 2 kg mass is rotating on a circular path of radius 0.8 m with angular velocity of 44 rad/sec. If r...

A 2 kg mass is rotating on a circular path of radius 0.8 m with angular velocity of 44 rad/sec. If radius of path becomes 1 m. Then the value of angular velocity will be:

A

28.16 rad/sec

B

35.16 rad/sec

C

19.28 rad/sec

D

8.12 rad/sec.

Answer

28.16 rad/sec

Explanation

Solution

Angular momentum,

L=mr2w = constant

ω2ω1=(r1r2)2=(0.81)2\frac{\omega_{2}}{\omega_{1}} = \left( \frac{r_{1}}{r_{2}} \right)^{2} = ⥂ \left( \frac{0.8}{1} \right)^{2}=0.64⇒ω2=44×0.64=28.166murads\omega_{2} ⥂ = ⥂ 44 \times 0.64 = 28.16\mspace{6mu}\frac{rad ⥂}{s}