Question: A 2 kg copper block is heated to 500<sup>0</sup>C and then it is placed on a large block of ice at 0...

Question

A 2 kg copper block is heated to 500⁰C and then it is placed on a large block of ice at 0⁰C. If the specific heat of copper is 400 J/kg/⁰C and latent heat of fusion of water is 3.5 × 10⁵ J/kg. The amount of ice that can melt is –

Answer 1

Solution

Q m₁ SDq = m₂L

\ m₂ = $\frac{m_{1}S\Delta\theta}{L}$ = $\frac{2 \times 400 \times 500}{3.5 \times 10^{5}}$ = $\frac{4}{3.5}$ = $\frac{8}{7}$ kg