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Question: A 2 kg block is lying on a smooth table which is connected by a body of mass 1 kg by a string which ...

A 2 kg block is lying on a smooth table which is connected by a body of mass 1 kg by a string which passes through a pulley. The 1 kg mass is hanging vertically. The acceleration of block and tension in the string will be

A

3.27m/s2,6.54N3.27 m / s ^ { 2 } , 6.54 N

B

4.38m/s2,6.54N4.38 m / \mathrm { s } ^ { 2 } , 6.54 N

C

3.27m/s2,9.86N3.27 m / s ^ { 2 } , 9.86 N

D

4.38m/s2,9.86N4.38 m / \mathrm { s } ^ { 2 } , 9.86 N

Answer

3.27m/s2,6.54N3.27 m / s ^ { 2 } , 6.54 N

Explanation

Solution

Acceleration =m2m1+m2×g= \frac { m _ { 2 } } { m _ { 1 } + m _ { 2 } } \times g =12+1×9.8=3.27 m/s2= \frac { 1 } { 2 + 1 } \times 9.8 = 3.27 \mathrm {~m} / \mathrm { s } ^ { 2 }

and T=m1a=2×3.27=6.54 NT = m _ { 1 } a = 2 \times 3.27 = 6.54 \mathrm {~N}