Question

A 2.24 L cylinder of oxygen at N.T.P. is found to develop a leakage. When the leakage was plugged the pressure dropped to 570 mm of Hg. The number of moles of gas that escaped will be

• A. 0.025
• B. 0 050
• C. 0.075
• D. 0.09

Answer 1

Answer: (A)

0.025

Answer 2

Find no. of moles of the gas leaked out by relation, $n = \frac{(drop \, in \, Pressure) \,V}{RT}$ = $\frac{190 \times 2.24}{760 \times 0.0821 \times 273} = 0.0249$ =0.025 moles