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Question: A 16 pF capacitor is connected to 70 V supply. The amount of electric energy stored in the capacitor...

A 16 pF capacitor is connected to 70 V supply. The amount of electric energy stored in the capacitor is.

A

4.5×10−12J4.5 \times 10^{- 12}J

B

5.1×10−8J5.1 \times 10^{- 8}J

C

2.5×10−12J2.5 \times 10^{- 12}J

D

3.2×10−8J3.2 \times 10^{- 8}J

Answer

5.1×10−8J5.1 \times 10^{- 8}J

Explanation

Solution

: Here, C=16pF=16×10−12FC = 16pF = 16 \times 10^{- 12}F

V=80VV = 80V

AsV=12CV2=12×16×10−12×(80)2=5.1×10−8JV = \frac{1}{2}CV^{2} = \frac{1}{2} \times 16 \times 10^{- 12} \times (80)^{2} = 5.1 \times 10^{- 8}J