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Question

Physics Question on electrostatic potential and capacitance

A 15 pF15\,pF capacitor is connected to a 60 V60\,V battery. How much electrostatic energy is stored?

A

2.77×10−8 J2.77\times 10^{-8}\,J

B

1.77×10−8 J1.77\times 10^{-8}\,J

C

2.35×10−8 J2.35\times 10^{-8}\,J

D

1.35×10−8 J1.35\times 10^{-8}\,J

Answer

2.77×10−8 J2.77\times 10^{-8}\,J

Explanation

Solution

Electrostatic energy U=12CV2U=\frac{1}{2} C V^{2}
=12(15×10−12)×(60)2=\frac{1}{2}\left(15 \times 10^{-12}\right) \times(60)^{2}
=12×15×36×10−12×102=\frac{1}{2} \times 15 \times 36 \times 10^{-12} \times 10^{2}
=270×10−10=270 \times 10^{-10}
=2.70×10−8J=2.70 \times 10^{-8} J