Question

A 12pF capacitor is connected to a 50V battery. How much electrostatic energy is stored in the capacitor?

Answer 1

Capacitor of the capacitance, C = 12 pF = 12 × 10−12

Potential difference, V = 50 V

Electrostatic energy stored in the capacitor is given by the relation,

$E =\frac{1}{2}CV^2=\frac{1}{2}×12×10^-12×( 50)^2 J =1.5×10^{-8 }J$

Therefore, the electrostatic energy stored in the capacitor is 1.5 × 10-8 J.