Question
Question: A \(100ml\) , \(0.1M\) solution of ammonium acetate is diluted by adding \(100ml\) of water. The \(p...
A 100ml , 0.1M solution of ammonium acetate is diluted by adding 100ml of water. The pH of the resulting solution will be ( pKa of acetic acid is nearly equal to pKb of NH4OH ):
A. 4.9
B. 5.0
C. 7.0
D. 10.0
Solution
Ammonium acetate is a salt which is prepared by using weak base and weak acid such as acetic acid and ammonium hydroxide. And when such salt is diluted with water then we use the relation given below to determine the pH of the resulting solution.
Formula used:
pH=7+21pKa−21pKb
Where, pH = potential of hydrogen of the solution
pKa = Strength of acid in the solution
pKb = Strength of base in the solution
Complete step by step answer:
Ammonium acetate is salt made up of acetic acid and ammonium hydroxide. Acetic acid is a weak acid and also ammonium hydroxide is a weak base.
The reaction takes place as:
CH3COOH+NH3OH→NH4CH3CO2+H2O
When this solution is diluted with 100ml of water then the pH of solution is given by:
pH=7+21pKa−21pKb
Where, pH = potential of hydrogen of the solution
pKa = Strength of acid in the solution
pKb = Strength of base in the solution
According to the question,
The strength of acetic acid is nearly equal to the strength of ammonium hydroxide.
So, we can write:
⇒pKa≃pKb
On substituting the values in the formula we will get:
pH=7+21pKa−21pKa
On further solving it we will get:
⇒pH=7+0 ⇒pH=7
Hence, option C is correct.
Note:
At room temperature250C , solutions which have pH less than 7 are acidic in nature and solutions which have pH greater than 7 are basic in nature. Solutions which have pH exactly equal to 7 at room temperature are neutral in nature for example water. The neutral value of the pH depends on the temperature, being lower than 7 if the temperature increases. The pH value can be less than 0 for very strong acids, or greater than 14 for very strong bases.