Question

A $100cc$ of carbon monoxide was mixed with excess of oxygen and exploded. Find the volume of oxygen used and the volume of carbon dioxide formed:
$A.$ $50cc,100cc$
$B.$ $100cc,150cc$
$C.$ $150cc,200cc$
$D.$ $200cc,250cc$

Answer 1

The volume of oxygen used and carbon dioxide formed in the given question can be found by Avogadro’s law, it states that under the same condition of temperature and pressure, equal volume of different gases contain equal number of molecules.

Complete step by step answer:
- Before solving the given question we have to write the balanced equation for the chemical reaction given in our question in terms of statement.
- Now, the balance chemical reaction involved when carbon monoxide $\left( {CO} \right)$ react with oxygen $\left( {{O_2}} \right)$ to form carbon dioxide $\left( {C{O_2}} \right)$ ,
$2CO + {O_2} \to 2C{O_2}$
- According to the Avogadro’ law equal volume of different gases contains equal numbers of molecules.
- In the reaction $2$ moles of the carbon monoxide react with $1$ mole of oxygen to produce $2$ moles of carbon dioxide. In the given question it is given that $100cc$ of carbon monoxide reacts with oxygen to produce carbon monoxide.
- We know that volume of gas is directly proportional to the number of moles.
- Hence, $2cc$ of carbon monoxide react with $1cc$ of oxygen to form $2cc$ of carbon dioxide
- So, $100cc$ of carbon dioxide reacts with $100 \times \dfrac{1}{2} = 50cc$of oxygen to produce $100cc$ of carbon dioxide.
Thus, the volume of oxygen used is $50cc$ and the volume of carbon dioxide formed is $100cc$ .

So, the correct option is $A$ .

Note:
Avogadro’s law investigates the relationship between the amount of gas and volume. It is a direct relationship between amount of gas and volume it means that volume of a gas is directly proportional to the number of moles the gases present in the sample. The law is important because it helps us save time and money in the long-run.