A 100 W bulb is connected to an AC source of 220 V, 50 Hz. T... | Physics | SolveeIt | Solveeit

Today, August 18

Question

A 100 W bulb is connected to an AC source of 220 V, 50 Hz. Then the current flowing through the bulb is

A

$\frac{5}{11} A$

B

$\frac{1}{2} A$

C

$2 \, A$

D

$\frac{3}{4} A$

Answer

$\frac{5}{11} A$

Explanation

Solution

$I = \frac{P}{V} = \frac{100}{220}$
$= \frac{5}{11} \,A$