Question

A $1.00 \times 10^{- 20}kg$ particle is vibrating with simple harmonic motion with a period of $1.00 \times 10^{- 5}\sec$ and a maximum speed of $1.00 \times 10^{3}m ⥂ / ⥂ s$. The maximum displacement of the particle is

• A. 1.59 mm
• B. 1.00 m
• C. 10 m
• D. None of these

Answer 1

Answer: (A)

1.59 mm

Answer 2

${v\frac{2\pi}{T}}_{\max}$ ⇒ $a = \frac{v_{\max}}{2\pi}$

$A = \frac{1.00 \times 10^{3} \times (1 \times 10^{- 5})}{2\pi} = 1.59$mm