Question
Question: A \( 100 \) meter long train is running at the speed of \( 30km/hr \) . How much time is taken by it...
A 100 meter long train is running at the speed of 30km/hr . How much time is taken by it to pass a man standing near the railway line?
(A) 10sec
(B) 11sec
(C) 12sec
(D) 20sec
Solution
Hint : For solving this particular question, we have to use the relationship between metres and kilometres that is 1km=1000m , we just have to apply v=td
Where ,
‘v’ is the speed in meters per second ,
‘d’ is the distance travelled by train in meters ,
And ‘t’ is the time taken by train to cover the distance in seconds .
Complete Step By Step Answer:
It is given that, the speed of train , v=30km/hr ,
And the length of the train, d=100m...............(1)
For crossing a man who is standing near the railway line, the train has to cover a distance equal its length, that is , d=100m .
As we know that speed is given as distance travelled per unit time .
Mathematically, we can write ,
v=td
Where ,
‘v’ is the speed in meters per second ,
‘d’ is the distance travelled by train in meters ,
And ‘t’ is the time taken by train to cover the distance in seconds .
We get ,
t=vd
Both the distance and speed should be in their corresponding standard unit.
We have distance already in its standard unit.
Now, we are converting speed into its standard unit ,
v=30km/hr=60×6030×1000m/sec
=650m/sec................(2)
Now, substitute (1),(2) in t=vd ,
We will get the following,
t=vd=650100 sec
Simply the above expression, we will get ,
t=50100×6 sec
Simply the above expression, we will get ,
∴t=12sec
Therefore, we can say that option ‘C’ is the correct option.
Note :
In the given question, no mathematical formula except the relation 1km=1000m and v=td
Where ,
‘v’ is the speed in meters per second ,
‘d’ is the distance travelled by train in meters ,
And ‘t’ is the time taken by train to cover the distance in seconds .
is being used only the mathematical operations such as addition, subtraction, multiplication and division is used. Questions similar in nature as that of above can be approached in a similar manner and we can solve it easily.