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Physics Question on thermal properties of matter

A 100 m100\, m long wire having cross-sectional area 625×10−4 m2625 \times 10^{-4} \, m ^2 and Young's modulus is 1010Nm−210^{10} Nm ^{-2} is subjected to a load of 250 N250 \, N, then the elongation in the wire will be:

A

6.25×10−3m6.25 \times 10^{-3} m

B

4×10−3m4 \times 10^{-3} m

C

4×10−4m4 \times 10^{-4} m

D

6.25×10−6m6.25 \times 10^{-6} m

Answer

4×10−3m4 \times 10^{-3} m

Explanation

Solution

The correct answer is B:
Elongation in wire δ=Fℓ​ /AY
δ=250×1006.25×10−4×1010\frac{250×100}{6.25×10^{−4}×10^{10}}\

δ=4×10−3m4×10^{−3}m