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Question

Physics Question on electrostatic potential and capacitance

A 10 μ\muF capacitor is charged to a potential difference of 1000 V. The terminals of the charged capacitor are disconnected from the power supply and connected to the terminals of an uncharged 6 μ\muF capacitor. What is the final potential difference across each capacitor?

A

167 V

B

100 V

C

625 V

D

250 V

Answer

625 V

Explanation

Solution

The capacitance of system of capacitors
\hspace40mm C = C_1 + C_2
\hspace40mm = 10 + 6 = 16 \mu F
The charge stored in first capacitor
\hspace40mm q = C_1 V
\hspace40mm = 10 \times 1000 = 10^4 \mu C
Final potential difference across each capacitor
\hspace40mm V' = q/C = 10^4 / 16
\hspace40mm = 625 \, volt