Question
Physics Question on electrostatic potential and capacitance
A 10 μF capacitor is charged to a potential difference of 1000 V. The terminals of the charged capacitor are disconnected from the power supply and connected to the terminals of an uncharged 6 μF capacitor. What is the final potential difference across each capacitor?
A
167 V
B
100 V
C
625 V
D
250 V
Answer
625 V
Explanation
Solution
The capacitance of system of capacitors
\hspace40mm C = C_1 + C_2
\hspace40mm = 10 + 6 = 16 \mu F
The charge stored in first capacitor
\hspace40mm q = C_1 V
\hspace40mm = 10 \times 1000 = 10^4 \mu C
Final potential difference across each capacitor
\hspace40mm V' = q/C = 10^4 / 16
\hspace40mm = 625 \, volt