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Question

Question: A 10 metre wire kept in east-west falling with velocity 5 m/sec perpendicular to the field\(0.3 \tim...

A 10 metre wire kept in east-west falling with velocity 5 m/sec perpendicular to the field0.3×104Wb/m20.3 \times 10^{- 4}Wb/m^{2}. The induced e.m.f. across the terminal will be

A

0.15 V

B

1.5 mV

C

1.5 V

D

15.0 V

Answer

1.5 mV

Explanation

Solution

Induced e.m.f.

=Blv=0.3×104×10×5= Blv = 0.3 \times 10^{- 4} \times 10 \times 5

=1.5×103V=1.56mumV= 1.5 \times 10^{- 3}V = 1.5\mspace{6mu} mV