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Question

Physics Question on Electromagnetic induction

A 10 m10\, m long horizontal wire extends from North East to South West. It is falling with a speed of 5.0 ms−15.0\,ms^{-1}, at right angles to the horizontal component of the earth's magnetic field, of 0.3×10−4 Wb/m20.3 \times 10^{-4}\,Wb/m^2. The value of the induced emf in wire is :

A

2.5×10−3V2.5 \times 10^{-3} V

B

1.1×10−3V1.1 \times 10^{-3}V

C

0.3×10−3V0.3 \times 10^{-3} V

D

1.5×10−3V1.5 \times 10^{-3} V

Answer

1.1×10−3V1.1 \times 10^{-3}V

Explanation

Solution

Induced emf =Bvℓsin⁡45= Bv \ell \sin 45
=0.3×10−4×5×10×12= 0.3 \times 10^{-4} \times 5 \times 10 \times \frac{1}{\sqrt{2}}
= 1.1×10−3V1.1 \times 10^{-3} V