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Question

Physics Question on tension

A 10kg10\, kg stone is suspended with a rope of breaking strength 30kgwt30 \,kg - wt. The minimum time in which the stone can be raised through a height 10m10\, m starting from rest is (Taking g=10Nkg1g =10 \,N\,kg ^{-1} )

A

0.5s0.5\,s

B

1.0s1.0\,s

C

23s\sqrt{\frac{2}{3}}\,s

D

2.0s2.0\,s

Answer

1.0s1.0\,s

Explanation

Solution

Tension in the string (T)=m×g(T)=m \times g
=30×10=300N=30 \times 10=300\, N

TMg=MaT-M g=M a
From the figure 30010×10a300-10 \times 10 a
a=20ms2\Rightarrow a=20 ms ^{-2}
Thus, the maximum acceleration with
which the stone can be raised is 20ms220 ms ^{-2}
Given, s=10ms=10 m
and u=0u=0
10=12(20)t2\therefore 10=\frac{1}{2}(20) t^{2}
t=1st=1\,s