Question

A 10 kg satellite completes one revolution around the earth at a height of 100 km in 108 minutes. The work done by the gravitational force of earth will be

• A.
• B.
• C. $\frac { 100 \times 10 } { 108 } J$
• D. Zero

Answer 1

Answer: (D)

Zero

Answer 2

Work done by centripetal force in circular motion is always equal to zero.