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Question: A 10 kg mass moves along x-axis. Its acceleration as a function of its position is shown in the figu...

A 10 kg mass moves along x-axis. Its acceleration as a function of its position is shown in the figure. What is the total work done on the mass by the force as the mass moves from x=8x = 8cm

A

8×10−2J8 \times 10 ^ { - 2 } J

B

C

D

Answer

8×10−2J8 \times 10 ^ { - 2 } J

Explanation

Solution

Work done on the mass = mass × covered area between the graph and displacement axis on a-t graph.

= 10×12(8×10−2)×20×10−210 \times \frac { 1 } { 2 } \left( 8 \times 10 ^ { - 2 } \right) \times 20 \times 10 ^ { - 2 }

= 8×10−28 \times 10 ^ { - 2 } J.