Solveeit Logo

Question

Question: A 10 g of a gas at atmospheric pressure is cooled from \(1.2 \times 10^{24}\) to \(3.01 \times 10^{2...

A 10 g of a gas at atmospheric pressure is cooled from 1.2×10241.2 \times 10^{24} to 3.01×10233.01 \times 10^{23} keeping the volume constant, its pressure would become

A

1/2 atm

B

1/273 atm

C

2 atm

D

273 atm

Answer

1/2 atm

Explanation

Solution

20oC20^{o}C

273oC273^{o}C

27oC27^{o}C ; 23oC- 23^{o}C

According to Gay-Lussac’s law

27oC27^{o}C 20oC20^{o}C 30oC30^{o}C atm; 27oC27^{o}C atm.