Question
Question: A 10 g of a gas at atmospheric pressure is cooled from \(1.2 \times 10^{24}\) to \(3.01 \times 10^{2...
A 10 g of a gas at atmospheric pressure is cooled from 1.2×1024 to 3.01×1023 keeping the volume constant, its pressure would become
A
1/2 atm
B
1/273 atm
C
2 atm
D
273 atm
Answer
1/2 atm
Explanation
Solution
20oC
273oC
27oC ; −23oC
According to Gay-Lussac’s law
27oC 20oC 30oC atm; 27oC atm.