Solveeit Logo
Login

Question

Question: A 10 cm long wire is placed horizontally on the surface of water and is gently pulled up with a forc...

A 10 cm long wire is placed horizontally on the surface of water and is gently pulled up with a force of 2×10−2N2 \times 10 ^ { - 2 } N to keep the wire in equilibrium. The surface tension in Nm–1 of water is

A

0.1 N/m

B

0.2 N/m

C

0.001 N/m

D

0.002 N/m

Answer

0.1 N/m

Explanation

Solution

Force on wire due to surface tension F=T×2lF = T \times 2 l

∴T=F2l=2×10−22×10×10−2=0.1 N/m\therefore T = \frac { F } { 2 l } = \frac { 2 \times 10 ^ { - 2 } } { 2 \times 10 \times 10 ^ { - 2 } } = 0.1 \mathrm {~N} / \mathrm { m }