Question
Question: A 10 µC charge is divided into two parts and placed at 1 cm distance so that the repulsive force bet...
A 10 µC charge is divided into two parts and placed at 1 cm distance so that the repulsive force between them is maximum. The charges of the two parts are:

A
2 µC and 8 µC
B
3 µC and 7 µC
C
4 µC and 6 µC
D
5 µC and 5 µC
Answer
The charges are 5 µC each.
Explanation
Solution
Let the two charges be q and 10−q µC. The repulsive force is proportional to the product:
F∝q(10−q)To maximize F, maximize the product q(10−q).
Differentiate:
dqd[q(10−q)]=10−2q=0⟹q=5μC.Thus, the charges are 5μC and 10−5=5μC.