Solveeit Logo

Question

Question: A 10 µC charge is divided into two parts and placed at 1 cm distance so that the repulsive force bet...

A 10 µC charge is divided into two parts and placed at 1 cm distance so that the repulsive force between them is maximum. The charges of the two parts are:

A

2 µC and 8 µC

B

3 µC and 7 µC

C

4 µC and 6 µC

D

5 µC and 5 µC

Answer

The charges are 5 µC each.

Explanation

Solution

Let the two charges be qq and 10q10 - q µC. The repulsive force is proportional to the product:

Fq(10q)F \propto q(10 - q)

To maximize FF, maximize the product q(10q)q(10 - q).

Differentiate:

ddq[q(10q)]=102q=0q=5μC.\frac{d}{dq}[q(10 - q)] = 10 - 2q = 0 \quad \Longrightarrow \quad q = 5 \, \mu C.

Thus, the charges are 5μC5\, \mu C and 105=5μC10 - 5 = 5\, \mu C.