Question

A 1 M solution of glucose reaches dissociation equilibrium according to equation given below ⇌$\mathrm { C } _ { 6 } \mathrm { H } _ { 12 } \mathrm { O } _ { 6 }$_. What is the concentration of HCHO at equilibrium if equilibrium constant is $6 \times 10 ^ { 22 }$.

• A.
• B.
• C.
• D.

Answer 1

Answer: (C)

Answer 2

$\mathrm { C } _ { 6 } \mathrm { H } _ { 12 } \mathrm { O } _ { 6 }$ forward reaction

$\mathrm { C } _ { 6 } \mathrm { H } _ { 12 } \mathrm { O } _ { 6 }$ backward reaction

$K _ { 2 } = \left[ \frac { 1 } { K _ { 1 } } \right] ^ { 1 / 6 }$; $K _ { 2 } = \left[ \frac { 1 } { 6 \times 10 ^ { 22 } } \right] ^ { 1 / 6 }$

$K _ { 2 } = 1.6 \times 10 ^ { - 4 }$M