Question

$A= (1, -2, 3), B = (2, 1, 3), C = (4, 2, 1)$ and $G = (-1, 3, 5)$ is the centroid of the tetrahedron ABCD. If $p= D_y$ and $q = D_z$ then $13p-1.1q =$

• A. 0
• B. 1
• C. -1
• D. 2

Answer 1

Answer: (A)

0

Answer 2

$\left(\frac{1+2+4+x}{4},\frac{-2 +1 +2 +y }{4},\frac{3+3+1+z}{4}\right)$ $= (-1 ,3,5)$