Question
Question: A 1.0 HP motor pumps out water from a well of depth 20 meters and fills a water tank of volume 2238 ...
A 1.0 HP motor pumps out water from a well of depth 20 meters and fills a water tank of volume 2238 liters at the height of 10 meters from the ground. The running time of the motor to fill the empty water tank is: (g=10ms−2)
A. 5 minutes
B. 10 minutes
C. 15 minutes
D. 20 minutes
Solution
Specific pump power is the measurement of electric power needed to operate a pump, relative to the volume flow rate. Also, 1 hp=746 Watts
In this question, the power of the motor is given, which is transferring the water from a well to a water tank. First, find the total potential energy required to transfer the water to 10+20=30m height from the well then find the time required.
Complete step by step answer:
Pump of 1 hp=746 Watts and the depth of the well is 20 meters.
Work done by a motor is equal to the change in the potential energy of water when it is pumped from the well to the overhead tank, where work done is given as, W=P∗t
Now assume the total time to fill the tank to be t seconds.
The total height the water is pumped is given as: 10+20=30 m
Now use the work done formula
The mass of the water, whose density is 1m3kg
m=density×volume =1m3Kg×2238m3 =2238KgSo the potential energy will be
PE=mgh =2238×10×30 =671400JAs per energy conservation rule work done by a motor is equal to the change in the potential energy of water; hence we can write
W=PE 746×t=671400 t=745671400 =900sec =15minThe total running time of the motor to fill the empty water tank is 15min
So, the correct answer is “Option C”.
Note:
The potential energy is the same as the work done in the same way kinetic energy is. Potential energy is a way of storing energy as of virtue of its motion while work is done is the way of changing energy from one form to another.