Question

A 0.10 kg block oscillates back and forth along a horizontal surface. Its displacement from the origin is given by: $x = (10cm)\cos\lbrack(10rad ⥂ / ⥂ s)t + \pi ⥂ / ⥂ 2rad\rbrack$. What is the maximum acceleration experienced by the block

• A. $10m ⥂ / ⥂ s^{2}$
• B. $10\pi m ⥂ / ⥂ s^{2}$
• C. $\frac{10\pi}{2}m ⥂ / ⥂ s^{2}$
• D. $\frac{10\pi}{3}m ⥂ / ⥂ s^{2}$

Answer 1

Answer: (A)

$10m ⥂ / ⥂ s^{2}$

Answer 2

$a = 10 \times 10^{- 2}m$ and $\omega = 10\mspace{6mu} rad/sec$

${A{2^{- 2}}^{2}\sec^{2}}_{\max}$