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Question: A 0.1 kg steel ball falls from a height of 10 m and bounces upto height 7m. If all the dissipated en...

A 0.1 kg steel ball falls from a height of 10 m and bounces upto height 7m. If all the dissipated energy was absorbed by the ball as heat, then its temperature rise would be :

[Given Ssteel = 0.11 kCal/kg0C]

A

0.0640C

B

0.0320C

C

0.1280C

D

None of these

Answer

0.0640C

Explanation

Solution

0.1 × 10 × (10 – 7) = 0.1 × 0.11× DT × 103 × 4.2

DT =30×0.14.2×11\frac { 30 \times 0.1 } { 4.2 \times 11 }= 0.0640C