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Question

Chemistry Question on Expressing Concentration of Solutions

A0.5g/LA\,\,0.5\,\,g/L solution of glucose is found to be isotonic with a 2.5g/L2.5\,\,g/L solution of an organic compound. What will be the molecular weight of that organic compound?

A

300300

B

600600

C

900900

D

200200

Answer

900900

Explanation

Solution

Molarity of glucose solution =0.5g180×1L=0.00277M=\frac{0.5\,\,g}{180\times 1L}=0.00277\,\,M Isotonic solution have equal molar concentrations, hence molarity of organic compound solution =0.00277M=0.00277\,\,M \therefore Molecular weight of compound =2.50.00277×1=900=\frac{2.5}{0.00277\times 1}=900