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Question

Physics Question on Alternating current

A 0.2kΩ0.2\, k\Omega resistor and 15μF15\,\mu F capacitor are connected in series to a 220V220\,V, 50Hz50\,Hz ac source. The impedance of the circuit is

A

250Ω250\, \Omega

B

268Ω268\, \Omega

C

29.15Ω29.15\, \Omega

D

291.5Ω291.5\, \Omega

Answer

291.5Ω291.5\, \Omega

Explanation

Solution

Here, R=0.2kΩ=200ΩR = 0.2\,k\Omega = 200\,\Omega C=15μF=15×106FC=15\,\mu F=15\times10^{-6}\,F, Vrms=220V,υ=50HzV_{rms}=220\,V, \upsilon=50\,Hz Capacitive reactance, XC=12πυCX_{C}=\frac{1}{2\pi\upsilon C} =12×3.14×50×15×106=\frac{1}{2\times3.14\times50\times15\times10^{-6}} =212Ω=212\,\Omega The impedance of the RCRC circuit is Z=R2+XC2Z=\sqrt{R^{2}+X^{2}_{C}} =(200)2+(212)2=\sqrt{\left(200\right)^{2}+\left(212\right)^{2}} =291.5Ω=291.5\,\Omega