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Chemistry Question on Solutions

A 0.0020M0.0020\, M aqueous solution of an ionic compound Co(NH3)5(NO2)ClCo \left( NH _{3}\right)_{5}\left( NO _{2}\right) Cl freezes at 0.00732C-0.00732^{\circ} C. Number of moles of ions which 1 mole of ionic compound produces on being dissolved in water will be : (kf=1.86C/m)\left( k _{ f }=1.86^{\circ} C / m \right)-

A

1

B

2

C

3

D

4

Answer

2

Explanation

Solution

ΔTf=ikf.m\Delta T _{ f } = ik _{ f }. m
i=ΔTfkfmi =\frac{\Delta T _{ f }}{ k _{ f } \cdot m }
=0.007321.86×0.002=0.007320.00372=\frac{0.00732}{1.86 \times 0.002}=\frac{0.00732}{0.00372}
i=2i =2

Compound will be [Co(NH3)5]NO5NO2]Cl\left.\left[ Co \left( NH _{3}\right)_{5}\right] NO _{5} NO _{2}\right] Cl

Total possible ions =2=2