Question: ${}_{92}^{238}U$decays through a series of transformations to a final stable nuclide. The particle...

Question

${}_{92}^{238}U$ decays through a series of transformations to a final stable nuclide. The particles emitted in the successive transformations are a b b a a

Which nuclide is not produced during this series of

transformations?

Accepted Answer

${}_{\mspace{6mu} 88}^{228}Ra$

Question: \({}_{92}^{238}U\)decays through a series of transformations to a final stable nuclide. The particle...

Solution