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Question

Question: 99% of a radioactive element will decay between....

99% of a radioactive element will decay between.

A

6 and 7 half lives

B

7 and 8 half lives

C

8 and 9 half lives

D

9 half lives

Answer

6 and 7 half lives

Explanation

Solution

N=N0(12)nNN0=(12)n1100=(12)n2n=100N = N_{0}\left( \frac{1}{2} \right)^{n} \Rightarrow \frac{N}{N_{0}} = \left( \frac{1}{2} \right)^{n} \Rightarrow \frac{1}{100} = \left( \frac{1}{2} \right)^{n} \Rightarrow 2^{n} = 100

n comes out in between 6 and 7.