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Question: $9 \times 10^{-7}$ laser operates the frequency $3 \times 10^{14} H_2$ and has aperture $10^{-2}$ w...

9×10−79 \times 10^{-7}

laser operates the frequency 3×1014H23 \times 10^{14} H_2 and has aperture 10−210^{-2} what will be the angular spread

Answer

The angular spread is 10.98×10−510.98 \times 10^{-5} radians.

Explanation

Solution

The angular spread of a laser beam due to diffraction from a circular aperture is given by θ=1.22λD\theta = 1.22 \frac{\lambda}{D}, where λ\lambda is the wavelength and DD is the aperture diameter. Using the given values λ=9×10−7\lambda = 9 \times 10^{-7} m and D=10−2D = 10^{-2} m, the angular spread is calculated as θ=1.22×9×10−710−2=1.22×9×10−5=10.98×10−5\theta = 1.22 \times \frac{9 \times 10^{-7}}{10^{-2}} = 1.22 \times 9 \times 10^{-5} = 10.98 \times 10^{-5} radians.