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Question: In the following reaction, what will be the product: $H_2C=CH_2 + H-OH + (O) \xrightarrow[KMnO4]{al...

In the following reaction, what will be the product:

H2C=CH2+H−OH+(O)→KMnO4alkaline?H_2C=CH_2 + H-OH + (O) \xrightarrow[KMnO4]{alkaline} ?

A

HO-H2C−CH2−CH2−OHH_2C-CH_2-CH_2-OH

B

HO-CH2−CH2−OHCH_2-CH_2-OH

C

H3C−CH∣−CH2−OHH_3C-\underset{|}{CH}-CH_2-OH OH

D

H2C=CH−CH2−OHH_2C=CH-CH_2-OH

Answer

HO‑CH₂‑CH₂‑OH

Explanation

Solution

Under cold, dilute alkaline KMnO₄ conditions, ethene undergoes syn-dihydroxylation, adding two –OH groups across the double bond to form ethylene glycol.