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Question

Question: $x^{2logx}=10x^2$...

x2logx=10x2x^{2logx}=10x^2

Answer

The solutions are x=101+32x = 10^{\frac{1 + \sqrt{3}}{2}} and x=10132x = 10^{\frac{1 - \sqrt{3}}{2}}.

Explanation

Solution

  1. Take log10\log_{10} on both sides of the equation.
  2. Apply logarithm properties to transform the equation into a quadratic form in terms of log10x\log_{10}x.
  3. Solve the quadratic equation for log10x\log_{10}x.
  4. Convert the logarithmic solutions back to find the values of xx.