Question

A phase difference of $5\pi$ corresponds to a path difference (in terms of $\lambda$) of : (Assume sources are in phase)

• A. $5\lambda$
• B. $10\lambda$
• C. $5\lambda/2$
• D. $2\lambda$

Answer 1

Answer: (C)

$\frac{5\lambda}{2}$

Answer 2

The relationship between phase difference ($\Delta\phi$) and path difference ($\Delta x$) is given by:

$\Delta\phi = \frac{2\pi}{\lambda} \Delta x$

Given $\Delta\phi = 5\pi$, we can solve for $\Delta x$:

$5\pi = \frac{2\pi}{\lambda} \Delta x$

$\Delta x = \frac{5\pi \lambda}{2\pi} = \frac{5\lambda}{2}$