Question

9.3 g of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product 'P'. The mass of product 'P' obtained is 26.4 g. The percentage yield is ......... %.

Answer 1

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93 g of aniline produces 330 g of 2,4,6-tribromoaniline.
Theoretical yield for 9.3 g of aniline:
$\frac{330}{93} \times 9.3 = 33 \, \text{g}$
Percentage yield:
$\text{Percentage yield} = \frac{\text{Actual yield}}{\text{Theoretical yield}} \times 100$
$\text{Percentage yield} = \frac{26.4}{33} \times 100 = 80\%$