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Question: The observer 'O' sees the distance AB as infinitely large. If refractive index of liquid is $\mu_1$ ...

The observer 'O' sees the distance AB as infinitely large. If refractive index of liquid is μ1\mu_1 and that of glass is μ2\mu_2, then μ1μ2\frac{\mu_1}{\mu_2} is -

Answer

sqrt(2)

Explanation

Solution

The limiting condition for a ray emerging at the edge leads via Snell’s law to μ1sinθc=μ2\mu_1\sin\theta_c=\mu_2 with θc=45\theta_c=45^\circ so that μ1μ2=1/sin45=2\frac{\mu_1}{\mu_2}=1/\sin45^\circ=\sqrt2.