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Question

Mathematics Question on permutations and combinations

8 persons has to travel from A to B in 3 allotted cars. If a car can carry maximum 3 persons. Then find the number of ways they can travel.

A

1880

B

1800

C

1680

D

1600

Answer

1680

Explanation

Solution

The correct option is (C): 1680
C1 C2 C3
3 3 2 \rightarrow
Total 8!3!3!2!2!\frac{8!}{3!3!2!2!} groups
So , they can travel in
8!3!3!2!2!×31 ways\frac{8!}{3!3!2!2!}\times31\ ways
=1680=1680