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Question

Question: $\lim_{x\to\infty}(1.00000001)^x$...

limx(1.00000001)x\lim_{x\to\infty}(1.00000001)^x

Answer

\infty

Explanation

Solution

The limit is of the form limxax\lim_{x\to\infty} a^x with a=1.00000001a = 1.00000001. Since the base aa is greater than 1, the exponential function axa^x grows unboundedly as xx approaches infinity.