Question

$7\log\left( \frac{16}{15} \right) + 5\log\left( \frac{25}{24} \right) + 3\log\left( \frac{81}{80} \right)$ is equal to

• A. 0
• B. 1
• C. $\log 2$
• D. $\log 3$

Answer 1

Answer: (C)

$\log 2$

Answer 2

Given expression = $\log\left( \frac{16^{7}}{15^{7}}.\frac{25^{5}}{24^{5}}.\frac{81^{3}}{80^{3}} \right) = \log 2$.