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Question: 75 kW engine is generating full power. It is able to provide a 700 kg airplane a speed 2.5 ms<sup>-1...

75 kW engine is generating full power. It is able to provide a 700 kg airplane a speed 2.5 ms-1. Find the fraction of engine power used.

A

1100\frac{1}{100}

B

3100\frac{3}{100}

C

3100\frac{3}{100}

D

7300\frac{7}{300}

Answer

7300\frac{7}{300}

Explanation

Solution

PusedPsupplied=F.VPsupplied=700×10×2.5750×103=7300\frac{P_{used}}{P_{\sup ⥂ plied}} = \frac{F.V}{P_{\sup ⥂ plied}} = \frac{700 \times 10 \times 2.5}{750 \times 10^{3}} = \frac{7}{300}