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Question

Chemistry Question on Some basic concepts of chemistry

74.5g74.5\, g of a metallic chloride contain 35.5g35.5\, g of chlorine. The equivalent weight of the metal is

A

19.5

B

35.5

C

39

D

78

Answer

39

Explanation

Solution

E wt. of metal = wt. of metal  wt. of chlorine ×35.5=\frac{\text { wt. of metal }}{\text { wt. of chlorine }} \times 35.5 \therefore E wt. of metal =74.535.535.5×35.5=39=\frac{74.5-35.5}{35.5} \times 35.5=39