Question
Question: Under what conditions is the force acting on a charge moving through a uniform magnetic field minimu...
Under what conditions is the force acting on a charge moving through a uniform magnetic field minimum?

The force acting on a charge moving through a uniform magnetic field is minimum when the velocity of the charge is parallel or anti-parallel to the direction of the magnetic field. In other words, the angle between the velocity vector and the magnetic field vector is 0∘ or 180∘.
Solution
The magnetic force F acting on a charge q moving with velocity v in a uniform magnetic field B is given by the Lorentz force formula:
F=q(v×B)The magnitude of this force is given by:
F=∣q∣vBsinθwhere:
- ∣q∣ is the magnitude of the charge.
- v is the magnitude of the velocity of the charge.
- B is the magnitude of the magnetic field.
- θ is the angle between the velocity vector v and the magnetic field vector B.
For the force F to be minimum, assuming the charge q, its velocity v (since it's moving), and the magnetic field B are non-zero, the value of sinθ must be minimum.
The minimum possible value of ∣sinθ∣ is 0.
This occurs under two conditions for the angle θ:
- When θ=0∘: The velocity vector v is parallel to the magnetic field vector B. In this case, sin(0∘)=0, so F=0.
- When θ=180∘: The velocity vector v is anti-parallel to the magnetic field vector B. In this case, sin(180∘)=0, so F=0.
Therefore, the minimum force acting on a charge moving through a uniform magnetic field is zero, and this occurs when the charge moves parallel or anti-parallel to the direction of the magnetic field.
The conditions for the force acting on a charge moving through a uniform magnetic field to be minimum are:
When the velocity vector of the charge is parallel or anti-parallel to the magnetic field vector. This means the angle between the velocity and the magnetic field is 0∘ or 180∘.