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Question: A motor boat is going in a river with a velocity $\overrightarrow{V}=(4\hat{i}-2\hat{j}+\hat{k})ms^{...

A motor boat is going in a river with a velocity V=(4i^2j^+k^)ms1\overrightarrow{V}=(4\hat{i}-2\hat{j}+\hat{k})ms^{-1}. If the force due to motor is F=(5i^10j^+6k^)N\overrightarrow{F}=(5\hat{i}-10\hat{j}+6\hat{k})N, then the power of the motor boat is:

A

100 W

B

50 W

C

46 W

D

23 W

Answer

46 W

Explanation

Solution

The power of a motor boat is given by the dot product of the force applied by the motor and the velocity of the boat. The formula for power PP is:

P=FVP = \vec{F} \cdot \vec{V}

Given:

Velocity of the boat, V=(4i^2j^+k^)ms1\overrightarrow{V}=(4\hat{i}-2\hat{j}+\hat{k}) \, ms^{-1}

Force due to the motor, F=(5i^10j^+6k^)N\overrightarrow{F}=(5\hat{i}-10\hat{j}+6\hat{k}) \, N

Substitute the given vectors into the power formula:

P=(5i^10j^+6k^)(4i^2j^+k^)P = (5\hat{i}-10\hat{j}+6\hat{k}) \cdot (4\hat{i}-2\hat{j}+\hat{k})

To calculate the dot product, multiply the corresponding components and sum them up:

P=(5)(4)+(10)(2)+(6)(1)P = (5)(4) + (-10)(-2) + (6)(1)

P=20+20+6P = 20 + 20 + 6

P=46WP = 46 \, W

Thus, the power of the motor boat is 46 W.