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Question

Physics Question on electrostatic potential and capacitance

6464 small drops of mercury, each of radius rr and charge qq coalesce to form a big drop. The ratio of the surface density of charge of each small drop with that of the big drop is

A

0.086111111

B

64:01:00

C

4:01

D

1:04

Answer

1:04

Explanation

Solution

Here R3=(4r)3  i.e. R=4rR^3 = (4r)^3 \, \, i.e. \, R = 4r
σ1σ2=r24r2=14\frac{\sigma_1}{\sigma_2} = \frac{r^2}{4r^2} = \frac{1}{4}